Question

Show your steps when solving the problem below. Container A has 800 mL of water and is leaking 6 mL per minute. Container B has 1,000 mL of water and is leaking minute. How many minutes will it take for the two containers to have the same amount of water?

Answer 1

Step 1 : Let's review the information given to us to answer the problem correctly:

• Container A = 800 ml - 6 ml per minute

,

• Container B = 1,000 ml - 10ml per minute

Step 2: Let's write the equation to solve the problem, as follows:

Let x to represent the number of minutes both containers have the same amount of water

Container A = Container B

800 - 6x = 1,000 - 10x

Like terms:

-6x + 10x = 1,000 - 800

4x = 200

Dividing by 4 at both sides:

4x/4 = 200/4

x = ?

I think you can calculate the value of x without problems.