Question

Looking at the two sets below, organize each set individually by arranging the bonds in order of decreasing polarity:1. C-P ; S-Br ; O-Cl2. N-Cl ; P-F ; N-O

Answer 1

Step-by-step explanation:

Here, we want to arrange the bonds in order of decreasing polarity

A polar bond occurs when there is an unequal electron sharing between the atoms in the bond. The greater the electronegativity difference between two atoms, the greater the bond polarity.

In most cases, the farther the elements are away from each other on the periodic table, the greater the polarity of the bond they form. A small value indicates a non-polar or covalent compound

Now let us make the arrangements: This would be from the most to the least polar bonds

1) for C-P (2.55-2.19 = 0.36)

S-Br (2.96 - 2.58 = 0.38)

O-Cl (3.44-3.16 = 0.28)

The values are the electronegativity values for each of the elements which is obtained from the electronegativity chart

S-Br > C-P > O-Cl

2) N-Cl (3.16-3.04 = 0.12)

P-F (3.98 - 2.19 = 1.79)

N-O (3.44 - 3.04 = 0.4)

P-F > N-O > N-Cl