Question

What is the slope of the secant line? Thank you

Answer 1

Given that,

The function is,

`f(x)=1.2x^3-37x^2+265x+555`

To find: To find the slope of the secant line from x1=0 and x2=4

Step-by-step explanation:

First we find the corresponding y values that is y1 and y2 for the given x1 and x2 respectively.

we get,

Whwn x1=0,

`y1=f(x1)=f(0)`

`f(0)=1.2(0)^3-37(0)^2+265(0)+555`
`f(0)=555`
`y1=555`

When x2=4, we get,

`f(4)=1.2(4)^3-37(4)^2+265(4)+555`
`f(4)=1099.8`

To find the slope of the line passing the points (0,555), (4,1099.8)

we know that,

Slope of the line passing through the points (x1,y1) and (x2,y2)

`m=(y2-y1)/(x2-x1)`

we get,

`m=(1099.8-555)/(4-0)`
`m=(544.8)/(4)`
`m=136.2`

Answer is:

Slope of the secant line from x1=0 and x2=4 is 136.2.