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Y= x^4-2x^3-8x^2+12x-16

1 Answer

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Y=x^4-2x^3-8x^2+12x-16

We will simplify further:


\begin{gathered} Y=x^4-2x^3-8x^2+12x-16 \\ when\colon x=0 \\ Y=0^4-2(0)^3-8(0^2+12(0)-16 \\ Y=-16 \\ \end{gathered}

Y= x^4-2x^3-8x^2+12x-16-example-1
User Ali Zia
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