Given the inequality:
![2-|3x-5|>-7](https://img.qammunity.org/2023/formulas/mathematics/high-school/n53utl5go8xvfzg40vwmk2y1widzcyw854.png)
To find x, follow the steps below.
Step 01: Isolate the absolute value.
To do it, first, subtract 2 from both sides of the inequality.
![\begin{gathered} 2-|3x-5|-2>-7-2 \\ 2-2-|3x-5|>-9 \\ -|3x-5|>-9 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/vgsarc5vm4gl58409ac8901aj9jnysx7fg.png)
Now, multiply the equation by -1:
![|3x-5|<9](https://img.qammunity.org/2023/formulas/mathematics/high-school/cxgy37mx3i9n6wq15g48nu7f6u8p50hr4k.png)
If |3x - 5| < 9, then 3x - 5 < 9 or -(3x - 5) < 9.
Step 02: Find the interval in which 3x - 5 < 9.
![3x-5<9](https://img.qammunity.org/2023/formulas/mathematics/high-school/2hrb2yjby4tlqks7t97yssh8xjyjhfqdv2.png)
Isolate x by adding 5 to both sides. In sequence, divide the sides by 3:
![\begin{gathered} 3x-5+5<9+5 \\ 3x<14 \\ (3x)/(3)<(14)/(3) \\ x<(14)/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/899hq6aiqh0sbu6qsax6fuecyjhnwnip9r.png)
Step 03: Find the interval in which -(3x - 5) < 9.
![-3x+5<9](https://img.qammunity.org/2023/formulas/mathematics/high-school/ji3o8gt1ytlz51dbc6diqly79zbpzjcilq.png)
To isolate x, first, subtract 5 from both sides. Second, divide the sides by 3. Finally, multiply the inequality by -1.
![\begin{gathered} -3x+5-5<9-5 \\ -3x<4 \\ (-3x)/(3)<(4)/(3) \\ -x<(4)/(3) \\ x>-(4)/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/d9iw0y5zl80amcy48ky9zm31oyriwz2j3o.png)
Step 04: Graph the interval.
Since x < 14/3 and x > -4/3:
Graphing the answer:
Step 05: Write your answer in interval notation.
![-(4)/(3)In interval notation: <p></p>[tex](-(4)/(3),(14)/(3))](https://img.qammunity.org/2023/formulas/mathematics/high-school/v9hfnr09et1hrzawxndd1noumkygs33fxc.png)
Step 06: Double-check the solution.
To double-check the solution, choose one point inside the interval and observe if the answer fits the equation. You can also choose a point outside the interval.
Let's choose x = 0 (inside the interval) and x = 5 (outside the interval).
![\begin{gathered} 2-|3x-5|>-7 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8v7xlttsqpyil1hoqcny51slc2s5tj7ig2.png)
Substituting x by 0.
![\begin{gathered} 2-|3\cdot0-5|>-7 \\ 2-|0-5|>-7 \\ 2-|5|>-7 \\ 2-5>-7 \\ -3>-7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/tdlu60rtt4ix0lxnc8o2tgqp788lykf2j8.png)
True.
Substituting x by 5.
![\begin{gathered} 2-|3x-5|>-7 \\ 2-|3\cdot5-5|>-7 \\ 2-|15-5|>-7 \\ 2-|10|>-7 \\ -8>-7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/89gcvetv2bw83vyw8orxh88irslpmbqtlz.png)
False, since -8 is not greater than -7. It is expected since 5 is not an answer for this inequality.
Answer:
![(-(4)/(3),(14)/(3))](https://img.qammunity.org/2023/formulas/mathematics/high-school/43kwjnndtpjs3ofqxsq7b1fu7lukkoo81f.png)