Okay, here we have this:
Considering the provided information, we are going to calculate the requested time, so we obtain the following:
![h(t)=-16t^2+10](https://img.qammunity.org/2023/formulas/mathematics/college/opmsb9ex83iymrt7mwya156fcf5tim60j5.png)
And he caught them at a height of 4 feet, so we'll substitute and solve for t:
![4=-16t^2+10](https://img.qammunity.org/2023/formulas/mathematics/college/t7ziqfgn99n5dak18u22agwz22mw3sbw5b.png)
Solving:
![\begin{gathered} 4=-16t^2+10 \\ -16t^2+10-10=4-10 \\ -16t^2=-6 \\ (-16t^2)/(-16)=(-6)/(-16) \\ t^2=(3)/(8) \\ t=\sqrt{(3)/(8)} \\ t\approx0.61 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u7vt7upjyk0bfwot8dhdk4g3mocgw5yij8.png)
Finally we obtain that the time where approximately 0.61.