Question

In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot

Answer 1

69.5 FT

Explanation:

\cos C = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{x}{95}

cosC=

hypotenuse

adjacent

​

=

95

x

​

\cos 43=\frac{x}{95}

cos43=

95

x

​

95\cos 43=x

95cos43=x

Cross multiply.

x=69.4786\approx \mathbf{69.5}\text{ feet}

x=69.4786≈69.5 feet