Question

Bacteria and viruses are inactivated by temperatures above 143 ∘C in an autoclave. An autoclave contains steam at 1.00 atm and 100 ∘C .At what pressure, in atmospheres, will the temperature of the steam in the autoclave reach 143 ∘C , if n and V do not change?Express the pressure to three significant figures and include the appropriate units.

Answer 1

At 1.12 atm.

Step-by-step explanation:

To calculate the pressure (P2), we can use the Gay-Lussac's Law replacing the values of P1 (1.00atm), T1 (100°C=373K) and T2 (143°C=416K):

`\begin{gathered} (P_1)/(T_1)=(P_2)/(T_2) \\ (1.00atm)/(373K)=(P_2)/(416K) \\ 0.00268(atm)/(K)=(P_2)/(416K) \\ 0.00268(atm)/(K)*416K=P_2 \\ 1.12atm=P_2 \end{gathered}`

Finally, at 1.12 atm will the temperature reach 143°C.