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4 votes
Find x...........
4 + √((x + 1)) = 0

1 Answer

7 votes

Due to the properties of the square root function,


\begin{gathered} \sqrt[]{(x+1)}\to\text{exists} \\ \Rightarrow x+1\ge0 \\ \Rightarrow x\ge-1 \\ \text{and} \\ \sqrt[]{y}\ge0 \end{gathered}

Solving the equation,


\begin{gathered} 4+\sqrt[]{(x+1)}=0 \\ \Rightarrow\sqrt[]{(x+1)}=-4!!! \end{gathered}

This is not possible since the square root is always greater or equal to zero; therefore, the equation has no solutions.

There is no real number such that multiplied by itself is equal to -4

User Vabarbosa
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