Question

In triangle ABC, ZA = 25°, ZC = 55°, and AB = 60. What are the approximate measures of the remaining side lengths ofthe triangle?

Answer 1

We have the next given information for the given triangle:

∠A= 25 degrees

∠C = 55 degrees

and

AB=60

To solve this, we need to use the Law of sines, which is given by:

`(\sin(A))/(a)=(\sin(B))/(b)=(\sin(C))/(c)`

Where ab= b = 60

Solve for a:

`(\sin(A))/(a)=(\sin(B))/(b)`
`a=(\sin (A))/((\sin (B))/(b))`
`a=(b\cdot\sin (A))/(\sin (B))`

Replacing the values:

`a=(60\cdot\sin (25))/(\sin (55))`

Then:

`a\approx31`

Now, we need to find the side lenght of c