Question

Determine the period of the following trigonometric function.2παy = 2 sin(5)

Answer 1

Given,

`y=-2\sin ((2\pi x)/(5))`

To find the period,

`\begin{gathered} y=-2\sin ((2\pi x)/(5)) \\ y=A\sin (Bx-c)+D \end{gathered}`

Then, the period is,

`\begin{gathered} =(2\pi)/(B) \\ =(2\pi)/(\pi) \\ =2 \end{gathered}`

Thus the period is 2