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2 votes
Please help me ASAP!!!!

User Elcharrua
by
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1 Answer

6 votes

By moving -4 to the right hand side, we get


\begin{gathered} |12-3x|=11+4 \\ |12-3x|=15 \end{gathered}

Now, by the properties of the absolute values, this last equation becomes in 2 conditions:


\begin{gathered} a)\text{ 12-3x=15} \\ b)12-3x=-15 \end{gathered}

From condition a), by moving 12 to the right hand side, we get


\begin{gathered} -3x=15-12 \\ -3x=3 \end{gathered}

and x is given by


\begin{gathered} x=(3)/(-3) \\ x=-1 \end{gathered}

Now, from condition b), by moving 12 to the right hand side, we have


\begin{gathered} -3x=-15-12 \\ -3x=-27 \end{gathered}

then, x is given by


\begin{gathered} x=(-27)/(-3) \\ x=9 \end{gathered}

Therefore, the answer is the union of both solution, that is, the answer is the third option: x=-1, 9

User Ahrimann Steiner
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