Answer:
17.21°C
Step-by-step explanation:
Using the following formula;
Q = m × c × ∆T
Where;
Q = amount of heat in joules
m = mass of substance in grams
c = specific heat capacity of water (4.184 J/g°C)
∆T = final temperature - initial temperature
According to the information provided in this question,
Q = 1,785 cal
1 cal = 4.184 J
1785 cal = 7468.4J
m = 343grams
c = 4.18J/g °C
initial temperature = 12°C
Using Q = m × c × ∆T
7468.4 = 343 × 4.18 × (T - 12)
7468.4 = 1433.74(T - 12)
7468.4 = 1433.74T - 17204.88
7468.4 + 17204.88 = 1433.74T
24673.28 = 1433.74T
T = 24673.28 ÷ 1433.74
T = 17.21°C