Given that the time is t = 10 s and the power is P = 50 W.
We have to find the work done.
The work done can be calculated by the formula
![\begin{gathered} P\text{ =}(W)/(t) \\ W=P* t \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/tdqhjvuort6iblwrwl3olfaj25ra9riypu.png)
Substituting the values, the work done will be
![\begin{gathered} W\text{ = 50}*10 \\ =500\text{ J} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/312f4vvkclhq7ywf1pktxuueeryrs83dyt.png)
Thus, the work done will be 500 J
The work done when time t' = 9.5 s is
![\begin{gathered} W^(\prime)=50*9.5 \\ =475\text{ J} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/l0fy8thgkmpiex7y4o02siec4yyxg5bh1m.png)
The less work done will be W-W' = 500-475 = 25 J
Sprinter has to do 25 J less work.