Question

Find the slope and a point on the line 1 y-9=-1/3 (x - 4)

Answer 1

we have the following:

`y-9=-(1)/(3)(x-4)`

we reduce the equation to the following form:

`y=mx+b`

where, m is the slope, now

`\begin{gathered} y=-(1)/(3)x+(4)/(3)+9 \\ y=-(1)/(3)x+(31)/(3) \end{gathered}`

therefore, the slope is -1/3

the point:

`\begin{gathered} x=0 \\ y=-(1)/(3)\cdot0+(31)/(3) \\ y=(31)/(3) \end{gathered}`

the point is (0, 31/3)