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38 votes
38 votes
if the temperature of 20.0 L of gas were increased to twice the initial value, while the pressure is held constant what would be the volume of the gas at the new temperature

User Idigyourpast
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1 Answer

16 votes
16 votes

Answer:

40 L

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 20 L

Initial temperature (T₁) = T

Final temperature (T₂) = 2T

Pressure (P) = constant

Final volume (V₂) =?

The new (i.e final) volume of the gas can be obtained as follow:

V₁/T₁ = V₂/T₂

20/T = V₂/2T

Cross multiply

T × V₂ = 20 × 2T

T × V₂ = 40T

Divide both side by T

V₂ = 40T /T

V₂ = 40 L

Therefore, the new volume of the gas is 40 L

User Yahia
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