Question

A tuna traveling at 12 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is its acceleration?

Answer 1

a = -1.2 m/s^2

Step-by-step explanation:

Vi = 12 m/s

Vf = 0 m/s

t = 10 s

Plug those values into the following equation:

Vf = Vi + at

0 = 12 + 10a

---> a = -1.2 m/s^2