Question

A bicycle tire of radius 0.40 m and mass 1.7kg is rotating at 62.9 rad/s.

What torque is necessary to stop the tire in 2.2 s?
Answer in units of N · m.
These are the last of my points, I have been scammed by people twice, someone please help me, this is actually physics but the scammers love physics.

Answer 1

T = taw

T = m r² ( w₂-w₁) / t

T = 1.7 × (0.40)² (0-62.9) / 2.2

T = 1.7 × 0.16 × -62.9 / 2.2

T = -17. 11 / 2.2

T = - 7.77 N.m