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Find the equation of the line whose slope is 2 and which passes through the point (-2, 3).

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Answer: y=2x+7

Explanation:

m=2 (-2,3)

A line in point-slope form is expressed as:

y-y₁=m(x-x₁)

m=2 x₁=-2 y₁=3

Hence,

y-3=2(x-(-2))

y-3=2(x+2)

y-3=2(x)+2(2)

y-3=2x+4

y-3+3=2x+4+3

y=2x+7

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