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A rectangle has a height of 2x^42x 4 2, x, start superscript, 4, end superscript and a width of x^2+8x+15x 2 +8x+15x, squared, plus, 8, x, plus, 15.

User Vwdewaal
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1 Answer

15 votes
15 votes

Question:

A rectangle has a height of 2x^4 and a width of x^2+8x+15. Calculate its area.

Answer:


Area = 2x^6 + 16x^5 + 30x^4

Explanation:

Given


Height = 2x^4


Width = x^2 + 8x + 15

Required

Determine the area of the rectangle

This is calculated as:


Area = Width * Height


Area = (x^2 + 8x + 15) * 2x^4


Area = 2x^6 + 16x^5 + 30x^4

User Darcyy
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