Question

NO LINKS!! Please help me with this horizontal ellipse. Part 1a​

Answer 1

`\textsf{c)} \quad (x^2)/(100)+(y^2)/(49)=1`

Explanation:

General equation of an ellipse

`((x-h)^2)/(a^2)+((y-k)^2)/(b^2)=1`

where the center is (h, k).

If the ellipse is horizontal then:

• a > b
• 2a is the major axis.
• 2b is the minor axis.

Given:

• Major axis = 20
• Minor axis = 14

Therefore:

`2a = 20 \implies a=10\implies a^2=100`

`2b=14 \implies b=7 \implies b^2=49`

Therefore the equation of the horizontal ellipse is:

`\boxed{(x^2)/(100)+(y^2)/(49)=1}`