Question

A dart is thrown horizontally at a target's center that is 5.00 m, away. The dart hits the target 0.150 m below the targets center. What is the initial velocity of the dart?

Answer 1

A dart is thrown horizontally at a target's center that is 5.00 m away. The dart hits the target 0.150 m below the target's center. We can ignore air resistance.

What was the initial horizontal velocity of the dart?

Answer: 28.6 m/s

Answer 2

v₀ₓ = 28.6 m / s

Step-by-step explanation:

This is a missile throwing exercise

y =
`v_(oy)` t - ½ g t²

as the dart is thrown horizontally the vertical velocity is zero (I go = 0)

y = - ½ g t²

t =
`\sqrt{- (2y)/(g) }`

let's calculate

t =
`\sqrt{- (2 \ (-0.150))/(9.8) }`

t = 0.175 s

the expression for horizontal displacement is

x = v₀ₓ t

v₀ₓ = x / t

v₀ₓ = 5.00 / 0.175

v₀ₓ = 28.6 m / s