Question

What would the molarity of a solution be if you took 10 mL of a 13 m stock solution and made it 300 mL solution

Answer 1

The molarity of the final solution is 0.43 M.

Step-by-step explanation:

To determine the molarity of the solution, we can use the equation:
M1V1 = M2V2

Where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this case, the initial molarity is 13 M, the initial volume is 10 mL, and the final volume is 300 mL. Plugging in these values into the equation, we get:
(13 M)(10 mL) = (M2)(300 mL)

Solving for M2, we find that the molarity of the final solution is 0.43 M.

Answer 2

0.43 M

Step-by-step explanation:

Use the dilution equation: M1V1 = M2V2

M1 = 13 M

V1 = 10 mL

M2 = ?

V2 = 300 mL

Solve for M2 --> M2 = M1V1/V2

M2 = (13 M)(10 mL) / (300 mL) = 0.43 M