hello
to solve this problem, we have to take individual point and test it with standard equation of an exponential
![y=ae^(\alpha x)](https://img.qammunity.org/2023/formulas/mathematics/college/eff2rm9n8zvwwg3w7c87lbaecrllxg3i6s.png)
now we work with the first point which is (0, 3)
put y = 3 and x = 0 in the equation
![\begin{gathered} y=ae^(\alpha x) \\ 3=ae^(\alpha(0)) \\ 3=a\cdot1 \\ a=3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/q5mlpgw7zchiyy8cxtasopjwpdmr1rpnrz.png)
now we know a = 3
we can test the second point which is (3, 375)
x = 3, y = 375 and a = 3
![\begin{gathered} y=ae^(\alpha x) \\ 375=3ae^(\alpha(3)) \\ \text{divide both sides by 3} \\ 125=e^(3\alpha) \\ \text{now we take the natural log of both sides} \\ In(125)=3\alpha \\ 3In5=3\alpha \\ \text{divide both sides by 3} \\ (3In5)/(3)=(3\alpha)/(3) \\ \alpha=In5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kxblqw0jwpj4c1xiu05bubjbb1iz194kx1.png)
now we can rewrite the equation of exponential function
![y=3ae^(In(5)(x))](https://img.qammunity.org/2023/formulas/mathematics/college/b1xy9395ujy6iqx2e1q5580zy1fd0b0jjw.png)
we can go ahead to plot the graph now