We are asked to determine the area of a triangle given two sides and the angle in-between. To do that we will use the following formula:

Where "a" and "b" are the sides of the triangle and "theta" is the angle in-between. Replacing the values we get:
![A=(1)/(2)(6\operatorname{cm})(15\operatorname{cm})\sin 142]()
Solving the operations:
![\begin{gathered} A=45\sin 142\operatorname{cm} \\ A=27.70cm^2 \end{gathered}]()
Therefore, the area is 27.70 square centimeters.