Question

Good morning I could really use help with this question please!

Answer 1

Given:

The charge of X is

`q_x=\text{ 7.5}*10^(-9)\text{ C}`

The charge of Y is

`q_y=-3.5*10^(-9)\text{ C}`

The distance between the charges is r = 80 cm.

To find whether there is an increase or decrease in the force of attraction/repulsion if the new charge of y is

`q_y^(\prime)=-6.5\text{ }*10^(-9)\text{ C}`

and the distance between the charges is the same.

Step-by-step explanation:

The charges q_x and q_y will have the force of attraction as they have opposite charges.

The magnitude of the force is given by the formula

`F=k(|q_x||q_y|)/(r^2)`

Here, the k is the electrostatic constant.

The distance between the charges is the same and the charge on X is also the same.

Thus, the force

`F\propto\text{ \mid q}_y|`

The new charge has a magnitude more than the old charge on Y.

Thus, the force of attraction will increase due to the increase in the magnitude of the charge.

Final Answer: The electrical force of attraction will increase.