Question

What is the equation of this line?

Answer 1

⇒If you check by inspection the line passes through the points (0,-3) and (2.-2)

⇒Note I only chose those points because they will help me figure out the gradient of the line . You van use the points of you choice to find the gradient using the formula

`m=(y_(2)-y_(1) )/(x_(2) -x_(1) ) \\m=(-2-(-3))/(2-0) \\m=(-2+3)/(2) \\m=(1)/(2)`

We know that the general equation to find the straight line equation is y=mx+c

⇒Now to find the value of the the unknown variable which in this case is c we can substitute the known (x,y) which is a point of your choice and m which is thew gradient you calculated above as variable m

⇒Note I will use the point (0,-3) to find the value of c

`-3=(1)/(2) (0)+c\\c=-3`

⇒This brings us to a conclusion of saying the equation of the straight line is :

⇒
`y=(1)/(2)x-3`

The first option is the answer

GOODLUCK!!!!!!!!