Given that the concrete column is in the form of a right prism with a hexagonal base, the formula for the volume is given below:
![\begin{gathered} \frac{3\sqrt[]{3}}{2}a^2h \\ \text{where a=50cm}=((50)/(100))m=0.5m \\ h=10m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jxqc1y4hisplmi6yu37ep13z4f6zag1yu6.png)
The volume of the concrete column would be:
![\begin{gathered} \frac{3\sqrt[]{3}}{2}*0.5^2*10m \\ =6.495m^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dyjq23y4qks1bi23jyyp197skkb6vh7nzf.png)
To get the lateral area, the lateral area is given by:

Hence, the volume of the concrete column is 6.495 cubic metres and the lateral area is 30 square metres.