Question

Factoring to find the zeros 2. n^2+7n+15=5

Answer 1

To solve the equation we write all the terms on the same side:

`\begin{gathered} n^2+7n+15-5=0 \\ n^2+7n+10=0 \end{gathered}`

now we factor the left side:

`(n+5)(n+2)=0`

then:

`\begin{gathered} n=-5 \\ or \\ n=-2 \end{gathered}`

Therefore the solutions are n=-5 and n=-2