Question:
Two sisters like to compete on their bike rides. Ciara can go 4 mph faster than her sister, Colleen. If it takes Colleen one hour longer than Ciara to go 80 miles, how fast can Colleen ride her bike?
Step-by-step explanation:
Note that Ciara can go 4mph faster than Collen.
Let's take the speed to ride a bike for Collen to be x mph.
The speed to ride a bike for Ciara will be (x + 4) mph
Now, to cover a distance of 80 miles, Collen takes 1 hour longer than Ciara. Applying the kinematics equation for motion at constant speed:
![v=(d)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/7bvf02ex7prlyl84jiizv8vikm7s8zddn1.png)
where v is velocity, d is distance and t is time, we can solve this equation for the time t:
![t=(d)/(v)](https://img.qammunity.org/2023/formulas/mathematics/college/bdb62x4ueqm5uveawhdmyloa60vt9qjx5f.png)
Here time Collen takes to cover a distance of 80 miles in 1 hour is more than that taken by Ciara, hence:
Time taken by Collen:
![t=(80)/(x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/5sz8ajf8dvk8ajik5xjhx209axx36tsqc0.png)
Time taken by Ciara:
![t=(80)/(x+4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/b5h501tf605qyukdzd1kkixckvlwzdplhp.png)
The equation for the difference in time:
![(80)/(x)\text{ - }\frac{80}{x+4\text{ }}=1](https://img.qammunity.org/2023/formulas/mathematics/high-school/b46ntz3s7vhy14l4wcej5vt7w6bobsrh9r.png)
Solve the equation for the difference in time to get the value of x which is Collen speed:
![x^2+4x\text{ - 320=0}](https://img.qammunity.org/2023/formulas/mathematics/high-school/t35qvy9vcj88mcymubye15h46z3hvv2tcx.png)
Solving the quadratic equation by the quadratic formula where a=1,b=4, and c=-320, we get:
![x=16](https://img.qammunity.org/2023/formulas/mathematics/high-school/51vz1wvw52f0u73j6lzndab62fxjbe9969.png)
Answer: Colleen's speed is 16 mph.