Question

1.are the events not on a leash and retriever independent 2.what is the probability that a dog that is a retriever is on a leash3.what is the probability that a dog that is not on a leash is not a retriever?4.what is the probability that a dog is not a retriever and is on a leash?

Answer 1

The total number of dogs are 135.

The number of Retrievers dogs are 35.

The number of off leashed playing dogs are 47.

Determine the number of dogs that are not Retrievers.

`\begin{gathered} NR=135-35 \\ =100 \end{gathered}`

Determine the number of dogs that are not retrievers and not lleashed.

`47-10=37`

So table can be filled as,

Not on a leash leashed Total

Retrievers 10 25 35

Not a Retrievers 37 63 100

Total 47 88 135

1.

The events are indpendent if occurence of event does not affect the other event. But it can be observed that not on a leash and retriever depend on each other. So event not on a leash and retriever are not indpendent.

4.

The number of dogs that are not retriever and is on a leash are 63. So probability is,

`\begin{gathered} P\text{ (R'}andL\text{)}=(63)/(135) \\ =(7)/(15) \end{gathered}`