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10x² + 11x - 6=0
a = 10, b = 11, c = −6
-
−11 ± √121 − 4(10)(–6)
2(10)

1 Answer

0 votes

Explanation:

what do we need to do ?

apply the general solution to such a quadratic equation and calculate the 2 solutions for x ?

yes, you started correctly.

x = (-11 ± sqrt(11² - 4×10×-6))/(2×10) =

= (-11 ± sqrt(121 + 240))/20 =

= (-11 ± sqrt(361))/20 =

= (-11 ± 19)/20

x1 = (-11 + 19)/20 = 8/20 = 2/5 = 0.4

x2 = (-11 - 19)/20 = -30/20 = -3/2 = -1.5

User Anton Beloglazov
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