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a Bismuth-210 has a half-life of about 5 days. After 17 days, how many milligrams of a 1,728 mg sample will remain? Round answer to the nearest tenth place. If answer does not have tenths place use a zero so that it does.

User Pitty
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1 Answer

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Explanation:

We have been given that Bismuth-210 has a half-life of about 5 days.

To solve our given problem we will use half-life formula.


y=a*((1)/(2))^{(t)/(b)}

Where,

a = Initial value,

t = Time,

b = half-life.

Given:


\begin{gathered} a=1728mg \\ t=17 \\ b=5 \end{gathered}

Therefore,


y=1728((1)/(2))^{(17)/(5)}

Simplify


y=163.69738\approx163.7mg

Hence, the answer is


163.7mg

User Jestges
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