Question

A swimmer can inhale exactly 0.25 moles of air before diving underwater. What will be the total volume of the swimmer’s lungs at 0.97 atm and 17.6 0C?

Answer 1

6.14 L

Step-by-step explanation:

To answer this question we'll use the PV=nRT formula, where:

• P = 0.97 atm

• V = ?

• n = 0.25 mol

• R = 0.082 atm·L·mol⁻¹·K⁻¹

• T = 17.6 °C ⇒ 17.6 + 273.16 = 209.76 K

We input the data:

• 0.97 atm * V = 0.25 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 209.76 K

And solve for V:

• V = 6.14 L