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F(n)=n^3-2n^2g(n)=-2n-1Find(f-g)(3)

User SargeATM
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1 Answer

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The function are given f(n)=n^3-2n^2 and g(n)=-2n-1 .

To determine the value of (f-g)(3) ,


(f-g)(3)=3^3-2*3^2+2*3+1=27-18+6+1
28-18+6=10+6=16

Hence the answer is 16.

User Avanek
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