You are saving to buy a car
You save $200 at the end of each month
The present, P = $200
At the rate of 2.4% compounded monthly,
Rate of return, r, will be
![r=((2.4)/(100))/(12)=(0.024)/(12)=0.002](https://img.qammunity.org/2023/formulas/mathematics/college/ss1mf7tzhogfxeop339or1ir6pgpkb5fwu.png)
Rate of return, r = 0.002
The deposit is made at the end of every month for 2 years,
Number of periods, n, will be
![n=2\text{ }*12=24](https://img.qammunity.org/2023/formulas/mathematics/college/bk7k0vwf596o2hrrn59yncpxoefxgpxf5s.png)
The formula to find the present value is
![FV=P\lbrack((1+r)^n-1)/(r)\rbrack](https://img.qammunity.org/2023/formulas/mathematics/college/clps6p71nh3ao4e8pbfck589gkxt73rr25.png)
Substiute the values into the formula
![\begin{gathered} FV=200\lbrack((1+0.002)^(24)-1)/(0.002)\rbrack \\ FV=200\lbrack((1.002)^(24)-1)/(0.002)\rbrack \\ FV=200\lbrack(0.049120363)/(0.002)\rbrack \\ FV=200(24.56) \\ FV=\text{ \$4912} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/n2g1pjexygr34qc592irg232hj4j3mhybh.png)
Hence, the future value is $4,912