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How to solve it? Each zero counted according to its multiplicity?

How to solve it? Each zero counted according to its multiplicity?-example-1
User Clemesha
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1 Answer

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Using the fundamental theorem of algebra which states that every polynomial equation of degree n with complex number coefficients has n roots, or solutions, in the complex numbers.

For:


f(x)=5x^5-2x^4+4x

n = 5

Therefore, the number of zeros of f(x) is 5

User Jonsson
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