30.6k views
2 votes
Find the roots of the equation 3x^2 + 45 = 0.

Find the roots of the equation 3x^2 + 45 = 0.-example-1

1 Answer

2 votes


+i√(15)\text{ ,-i}√(15)

Step-by-step explanation

A root is a value for which a given function equals zero, so let's solve the equation

Step 1


3x^2+45=0

a) apply the subtraction property of equality and subtract 45 in both sides


\begin{gathered} 3x^2+45=0 \\ 3x^2+45-45=0-45 \\ 3x^2=-45 \end{gathered}

b)now, use the division property of equality to isolate square x,


\begin{gathered} 3x^2=-45 \\ divide\text{ both sides by 3} \\ (3x^2)/(3)=(-45)/(3) \\ x^2=-15 \end{gathered}

c) finally , take the square root in both sides


\begin{gathered} x^(2)=-15 \\ √(x^2)=√(-15) \\ x=\pm√(15)i \\ x=\pm i√(15) \end{gathered}

so, the answer is


+i√(15)\text{ ,-i}√(15)

I hope this helps you

User Andrei Ashikhmin
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.