From the problem, we have :
![\lvert5-x\rvert>6](https://img.qammunity.org/2023/formulas/mathematics/college/lrh2nlhr1n93ytv5nj8r7at2rcrlg12tgn.png)
In solving absolute values, we need to take the positive and negative values of the terms outside the absolute value sign.
This will be :
![\begin{gathered} 5-x>6 \\ 5-x>-6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hra353gsqkt0eaivcxouz1ejienuvxdgj7.png)
We will form two inequalities.
Solve for the solutions :
For the first inequality,
![\begin{gathered} 5-x>6 \\ -x>6-5 \\ -x>1 \\ \text{Note that multiplying a negative number will change the symbol} \\ \text{Multiply by -1} \\ x<-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kcym0qrsxf0e55jx57aoe1af876esbjx26.png)
For the second inequality,
![\begin{gathered} 5-x>-6 \\ -x>-6-5 \\ -x>-11 \\ \text{Multiply by -1} \\ x<11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4xdz3ja4v9rh9wsf8hb55pi1ena3y97pzt.png)
So we have x < -1 and x < 11
From these two solutions, x < -1 will govern since that inequality needs a value of x less than -1 and some of the numbers less than 11 will not apply to it.
So the answer is x < -1
The graph will be :
The end point is an open circle because the symbol is <