Question

A parabola has the equation y = x2 - 10x + 28. What are the coordinates of its vertex?h Enter your answer in the box with parenthesis but no spaces in the form

Answer 1

We have the parabola:

`y=x^2-10x+28`

There is one expression that gives you the x-coordinate of the vertex:

`-(b)/(2a)`

We know that the standard form of a quadratic function is: ax^2+bx+c, then:

`-((-10))/(2(1))=(10)/(2)=5`

Now, having x=5 we can substitute it on the original equation:

`\begin{gathered} y=(5)^2-10(5)+28 \\ y=25-50+28 \\ y=3 \end{gathered}`

The vertex of the parabola is (5, 3)