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A city council consists of 10 members. Four are Republicans, three are Democrats, and three are Independents. If a committee of three is to be selected, find the probability of selectinga. All Republicansb. All Democrats

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We have a total of 10 members to choose from, this means that we have a total of 10 possibilities.

a.

We have four republicans and we need to choose three of them, the number of ways to do this is:


_4C_3=(4!)/(3!(4-3)!)=4

Since we are going to choose 3 people of the total of 10 members the number of ways to do this is:


_(10)C_3=(10!)/(3!(10-3)!)=120

The probability of choosing all republicans is:


P=(4)/(120)=(1)/(30)

Therefore the probability is 1/30

b.

In this case we need to choose 3 people out of 3 people (since we only have 3 democrats) there's only one way to do this.

Then in this case the probability is:


P=(1)/(120)

Therefore the probability of choosing all democrats is 1/120

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