Question

Please help me help help me please help help me

Answer 1

We have to solve for x.

We will apply the logarithm properties.

`\begin{gathered} 2^(x-1)=31 \\ \log _2(2^(x-1))=\log _2(31) \\ x-1=\log _2(31) \\ x=\log _2(31)+1 \\ x\approx4.9542+1 \\ x\approx5.9542 \end{gathered}`

Answer: x = 5.9542