Answer:
0.86
Explanation:
Given:
• The percentage who like pepperoni pizza, Pr(P)=45%=0.45
,
• The percentage who like cheese pizza, Pr(C)=72%=0.72
,
• The percentage who like both, Pr(P∩C)=31%=0.31
We want to find the probability that a randomly selected student likes pepperoni pizza OR cheese pizza, Pr(P∪C).
From probability theory:
![\begin{gathered} Pr(P\cup C)=Pr(P)+Pr(C)-Pr(P\cap C) \\ =0.45+0.72-0.31 \\ =0.86 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zxp335cmoytmp59zjgw4t9qsnyc6ofr8md.png)
The probability that a randomly selected student likes pepperoni pizza OR cheese pizza is 0.86.