19.4k views
1 vote
I need help filling out this worksheet. I would appreciate a VERY QuICK and eAsy ANsweRRrrr.

I need help filling out this worksheet. I would appreciate a VERY QuICK and eAsy ANsweRRrrr-example-1
User Dazonic
by
7.6k points

1 Answer

3 votes

Answer:

1.58 m/s

Step-by-step explanation:

By the conservation of momentum, we can write the following equation


\begin{gathered} p_i=p_f \\ m_1v_(1i)=(m_1+m_2)v_f \end{gathered}

Where m1 is the mass of the first car, v1i is the speed of this car, m2 is the mass of the second car and vf is the final speed. So, we need to solve for vf as


v_f=(m_1v_(1i))/(m_1+m_2)

Replacing m1 = 13,500 kg, v1i = 4.5 m/s, and m2 = 25,000 kg, we get


v_f=\frac{13,500\text{ kg \lparen4.5 m/s\rparen}}{(13,500\text{ kg + 25,000 kg\rparen}}=1.58\text{ m/s}

Therefore, the speed of the two cars after the collision is 1.58 m/s

User Felixbade
by
7.0k points