GIVEN:
We are given a right angled triangle with sides and angles as indicated.
Required;
We are required to use the information given to calculate the missing sides, x and y.
Step-by-step solution:
We have a right angled triangle with the reference angle given as 60 degrees. Therefore, the sides will be labelled as follows;

To calculate the side labeled x, we would use the trig ratio which is,

Therefore;

We shall apply the values of special angles. For a trigonometric calculation with right angled triangles,

The equation can now be refined and written as follows;

Now we cross multiply;

Next we calculate the value of y. We shall use the ratio;

Hence;

The cosine of 60 degrees is,

We substitute this into the equation above;

Therefore the missing sides are;
ANSWER:

x = 8√3
y = 8