Question

Hello, how do you find the slope of the line that contained the points (6, -10) and (-18, 6)

Answer 1

Remember that

The formula to calculate the slope between two points is equal to

`m=(y2-y1)/(x2-x1)`

In this problem we have

(6, -10) and (-18, 6)

so

(x1,y1)=(6,-10)

(x2,y2)=(-18,6)

substitute in the formula

`\begin{gathered} m=(6-(-10))/(-18-6) \\ m=(6+10)/(-24) \\ \\ m=(16)/(-24) \end{gathered}`

simplify

`m=-(16)/(24)=-(4)/(6)=-(2)/(3)`

the slope is -2/3