Question

How do i find antilog of log3a + log4a- 2log a?

Answer 1

Given

`log3a+log4a-2loga`

We can find the antilog below;

Step-by-step explanation

`\begin{gathered} log3a+log4a-2loga \\ =log3a+log4a-loga^2 \\ =log((3a*4a)/(a^2)) \\ =log12 \end{gathered}`

Therefore, the antilog becomes of the above becomes;

`antilog(log12)=12`

Answer: 12