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The vertices of ABC are A(2, - 2), B(-2, - 2), and C(4,4). For the translation below, give the vertices of AA'B'C'. T(24)(ABC) The vertices of AA'B'C' are A and c'o (Simplify your answers. Type ordered pairs.)

The vertices of ABC are A(2, - 2), B(-2, - 2), and C(4,4). For the translation below-example-1
User Grobu
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The given vertices are A(2, -2), B(-2, -2), and C(4,4).

The given transformation is


T_((2,4))(\Delta ABC)

This transformation means an addition of 2 units to x-coordinates and an addition of 4 to y-coordinates. So, the new transformations are

A'(2+2, -2+4) = A'(4, 2).

B'(-2+2, -2+4) = B'(0, 2)

C'(4+2, 4+4) = C'(6, 8).

Therefore, the vertices are A'(4, 2), B'(0, 2), and C'(6, 8).

User ReverseFlowControl
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