Question

Let f(x) = 2x - 1 and g(x) = -x squared + x-3. Which equation shows h(x), where h(x) = f(x) x g(x)?

Answer 1

h(x) = -2x³+3x²-7x+3

1) Considering that f(x)= 2x-1 and g(x)= -x²+x-3 let's find out h(x) multiplying f(x) by g(x). Note that we'll distribute those factors (FOIL)

`\begin{gathered} f\mleft(x\mright)=2x-1 \\ g\mleft(x\mright)=-x^(2)+x-3 \\ (2x-1)(-x^2+x-3) \\ -2x^3+2x^2-6x+x^2-x+3 \\ h(x)=-2x^3+3x^2-7x+3 \end{gathered}`

2) Hence, the answer is h(x) = -2x³+3x²-7x+3