Question

The perimeter of a rectangle is 222 millimeters. if the length is 60 millimeters .what is the width?

Answer 1

Given :

The perimeter of the rectangle = p = 222 mm

And the length of the rectangle = l = 60 mm

Let the width = w

The perimeter of the rectangle = p = 2 ( l + w )

so,

`\begin{gathered} p=2\cdot(l+w) \\ 222=2(60+w) \end{gathered}`

solve the equation to find w:

`\begin{gathered} (222)/(2)=60+w \\ 111=60+w \\ 111-60=w \\ \\ w=51 \end{gathered}`

The answer is : the width of the rectangle = 51 mm